Clausius-Clapeyron Equation:
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The Clausius-Clapeyron equation describes the relationship between vapor pressure and temperature for a substance. It's used to calculate the enthalpy of vaporization (ΔH_v), which is the energy required to vaporize one mole of a liquid at constant temperature and pressure.
The calculator uses the Clausius-Clapeyron equation:
Where:
Explanation: The equation relates the natural logarithm of vapor pressure to the reciprocal of temperature, with the slope proportional to the enthalpy of vaporization.
Details: Enthalpy of vaporization is a crucial thermodynamic property that indicates the strength of intermolecular forces in a liquid. It's important in chemical engineering, meteorology, and materials science for designing separation processes, predicting weather patterns, and understanding substance behavior.
Tips: Enter the gas constant (typically 8.314 J/mol·K), two different temperatures in Kelvin, and the corresponding vapor pressures in Pascals. Ensure T₂ ≠ T₁ and all values are positive.
Q1: What units should I use for this calculation?
A: Use Kelvin for temperature, Pascals for pressure, and J/mol·K for the gas constant. The result will be in J/mol.
Q2: Why must temperatures be in Kelvin?
A: The equation requires absolute temperature values, as it involves ratios and differences of temperatures.
Q3: Can I use different pressure units?
A: Yes, but both pressures must be in the same units, and you'll need to adjust the gas constant accordingly.
Q4: What if T₁ and T₂ are too close together?
A: The calculation becomes less accurate when temperature differences are small. For best results, use temperatures that are at least 10K apart.
Q5: Does this equation work for all substances?
A: The equation works best for substances that obey the ideal gas law and have constant enthalpy of vaporization over the temperature range.